First, we will need to determine the slopes of two lines - lines AB and BC.
Slope Line AB = (y1 -y2) ÷ (x1 -x2) = (2 --4) ÷ (9 -3) = (6) ÷ (6) = 1
Slope Line BC = (y3 -y2) ÷ (x3 -x2) = (-6 --4) ÷ (5 -3) = (-2) ÷ (2) = -1
Now, we need to find the 'x' coordinate of the circle's center which is:
xctr = [slope AB * slope BC * (Y3 -Y1) + slope AB * (X2 +X3) -slope BC * (X1 +X2)] ÷ [2 * (slope AB -slope BC)]
xctr = [ (1 * -1 * (-6 -2)) + (1 * (3 + 5)) - (-1 * (9 + 3))] ÷ 2 * (1 --1)
xctr = (-1 * (-8)) + 8 -(-12) ÷ 4
xctr = (8 + 8 + 12) ÷ 4
xctr = 7
To find the 'y' coordinate of the circle's center we use this formula:
yctr = -(1/slope AB)*(xctr-[(x1 +x2)/2)] + (y1 +y2)/2
yctr = -(1/1) * (7 -[(9 +3)/2]) + (2 -4)/2
yctr = (-1 * (7 -6)) -(2/2)
yctr = (-1 * 1) -1
yctr = -2
Circle's Center is located at: (7, -2)
Finally, to calculate the circle's radius, we use this formula:
radius = Square Root [(x1 -xCtr)^2 + (y1 -yCtr)^2)]
where (x1, y1) can be any of the three points but let's use (9, 2)
radius = Square Root [(9 -7)^2 + (2 --2)^2)]
radius = Square Root [(2)^2 + (4)^2)]
radius = Square Root (20)
radius = 4.472135955
To calculate the circle's equation, insert those three numbers into this equation.